Resolução Física - Halliday - Vol 1, 2, 3, 4 - 8ª Ed (1)

(Parte 2 de 2)

42. (a) The receptacle is a volume of (40 cm)(40 cm)(30 cm) = 48000 cm3 = 48 L = (48)(16)/1.356 = 67.63 standard bottles, which is a little more than 3 nebuchadnezzars (the largest bottle indicated). The remainder, 7.63 standard bottles, is just a little less than 1 methuselah. Thus, the answer to part (a) is 3 nebuchadnezzars and 1 methuselah.

(b) Since 1 methuselah.= 8 standard bottles, then the extra amount is 8 − 7.63 = 0.37 standard bottle.

(c) Using the conversion factor 16 standard bottles = 1.356 L, we have

1.356 L0.37 standard bottle (0.37 standard bottle)0.26 L. 16 standard bottles

4. Equation 1-9 gives (to very high precision!) the conversion from atomic mass units to kilograms. Since this problem deals with the ratio of total mass (1.0 kg) divided by the mass of one atom (1.0 u, but converted to kilograms), then the computation reduces to simply taking the reciprocal of the number given in Eq.1-9 and rounding off

45. We convert meters to astronomical units, and seconds to minutes, using

= Thus, 3.0 × 108 m/s becomes

46. The volume of the water that fell is

We write the mass-per-unit-volume (density) of the water as:

48. The mass of the pig is 3.108 slugs, or (3.108)(14.59) = 45.346 kg. Referring now to the corn, a U.S. bushel is 35.238 liters. Thus, a value of 1 for the corn-hog ratio would be equivalent to 35.238/45.346 = 0.76 in the indicated metric units. Therefore, a value of 5.7 for the ratio corresponds to 5.7(0.7) ≈ 4.4 in the indicated metric units.

49. Two jalapeño peppers have spiciness = 8000 SHU, and this amount multiplied by 400

single habanero pepper

More precisely, 10.7 habanero peppers will provide that total

(the number of people) is 3.2×106 SHU, which is roughly ten times the SHU value for a required SHU value.

m km

(Parte 2 de 2)